python实现简单的井字棋(落子平局)

本文实例为大家分享了python实现简单的井字棋的具体代码，供大家参考，具体内容如下

使用python实现井字棋游戏，没有具体算法，只是用随机下棋简单实现：

import random
board = [['+','+','+'],['+','+','+'],['+','+','+']]
def ma(board):
 if isempty(board):
  a = random.randint(0, 2)
  b = random.randint(0, 2)
  if board[a][b] != 'X' and board[a][b] != 'O':
print("机器走：")
board[a][b] = 'O'
oput(board)
  else:
ma(board)
 else:
  print("平局")
def oput(board):
 print("  0 1 2")
 for i in range(3):
  print(i, end=' ')
  for j in range(3):
print(board[i][j], end=" ")
  print("")
def winput(i,j):
 if board[i][j] == 'X':
  print("human win")
 else:
  print("machine win")
 return 1
def test(board):
 for i in range(3):
  for j in range(3):
if board[i][j] != '+':
 if j == 0:
  if board[i][j] == board[i][j + 1] == board[i][j + 2]:return winput(i,j)
 if i == 0:
  if board[i][j] == board[i + 1][j] == board[i + 2][j]:return winput(i,j)
 if i == 0 and j == 0:
  if board[i][j] == board[i + 1][j + 1] == board[i + 2][j + 2]:return winput(i,j)
 if i == 2 and j == 0:
  if board[i][j] == board[i - 1][j + 1] == board[i - 2][j + 2]:return winput(i,j)
def isempty(board):
 for i in range(3):
  for j in range(3):
if board[i][j] == '+':
 return True
 return False
def main():
 print("初始棋盘：")
 oput(board)
 flag = 0
 t = input("human first? Y/N  human for X, machine for O\n")
 if t == 'Y':
  while isempty(board):
print("人走：  ")
a, b = map(int, input("输入落子纵横坐标： a,b \n").split(','))
if board[a][b] == '+':
board[a][b] = 'X'
oput(board)
flag = test(board)
if flag == 1:
break
else:
 print("落子位置不对")
 continue
ma(board)
flag = test(board)
if flag == 1:
 break
if isempty(board) == 0 and flag == 0:
 print("平局")
 break
 elif t == 'N':
  while isempty(board):
ma(board)
flag = test(board)
if isempty(board) == 0 and flag == 0:
 print("平局")
 break
if flag == 1:
 break
print("人走：  ")
a, b = map(int, input("输入落子纵横坐标： a,b \n").split(','))
if board[a][b] == '+':
 board[a][b] = 'X'
 oput(board)
 flag = test(board)
 if flag == 1:
  break
else:
 print("落子位置不对")
 continue
if __name__ == "__main__":
 main()

结果：