Python实战小项目之身份证信息校验

weights=[7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2]

verification_dict={0:1,
 1:0,
 2:"X",
 3:9,
 4:8,
 5:7,
 6:6,
 7:5,
 8:4,
 9:3,
 10:2}

import pandas as pd
import numpy as np
data = pd.read_excel('身份证区域代码完整版.xls')
# 读取18位身份证
sfz=input()
# 对身份证信息切片
position=int(sfz[0:6])
birthday=sfz[6:14]
police_code=sfz[14:16]
sex_code=int(sfz[16])
verification=int(sfz[17])
# 获取区域名字，如福建省龙岩市永定县
position_name=data.iloc[data.loc[data['代码'] == position].index[0]]['名称']
# 确定性别，并确定是该登记所第几个登记的
def sex(n):
 train_list=[]
 male_list=[1,3,5,7,9]
 female_list=[0,2,4,6,8]
 if n in male_list:
  train_list.append('男')
  train_list.append(male_list.index(n)+1)
 else:
  train_list.append('女')
  train_list.append(female_list.index(n)+1)
 return train_list
# 校验算法
weights=[7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2]
sfz_code=[]
for item in sfz:
 sfz_code.append(int(item))
 
weights_sfz=[]
for i in sfz_code:
 for j in weights:
  weights_sfz.append(i*j)
# 找到余数
target=sum(weights_sfz)%11
verification_dict={0:1,
 1:0,
 2:"X",
 3:9,
 4:8,
 5:7,
 6:6,
 7:5,
 8:4,
 9:3,
 10:2}
# 找到余数对应的第18位校验码
def verification_whether(target_n):
 return verification_dict[target_n]
# 看看输入的身份证校验码和算出来的校验码是否一致，如果不一致，则是假身份证
def verification_true_false(sfz_verification,target_n_whether):
 if sfz_verification == target_n_whether:
  return "真"
 else:
  return "假"
# 将结果格式化打印出来
print("性别  ：",sex(sex_code)[0])
print("地区  ：",position_name)
print("出生年月日： {}年{}月{}日".format(birthday[0:4],birthday[4:6],birthday[6:8]))
print("出生当日派出所登记的第 {} 个{}孩".format(sex(sex_code)[1],sex(sex_code)[0]))
print("校验码：",verification)
print("身份证号真伪性：",verification_true_false(verification,verification_whether(target)))